Gerund 판단 함수만들기

# Make a function gerund_infinitive that, given a string ending in "ing",

# returns the rest of the string prefixed with "to ". If the string

# doesn't end in "ing", return "That's not a gerund!"

#

# >>>> gerund_infinitive("building")

# to build

# >>>> gerund_infinitive("build")

# That's not a gerund!

def gerund_infinitive(string):

# Add code here that returns the answer

stringLength = len(string)

isGerund = ""

for i in range(stringLength - 3, stringLength):

isGerund += string[i]

if(isGerund == "ing"):

string = "to " + string[0:stringLength - 3]

else:

string = "That's not a gerund!"

return string

# Add more statements to test what your function does:

print (gerund_infinitive("building"))

print (gerund_infinitive("build"))

Python 3.6.1 (default, Dec 2015, 13:05:11)
[GCC 4.8.2] on linux
   
to build
That's not a gerund!

Reference site : https://hourofpython.trinket.io/python-challenges#/string-challenges/gerund-slicing-challenge